In Python, printing leading zero for hex numbers 0 through f
This is probably a simple question for an experienced Python person:
This is a little python program that gets 3 random hex numbers and prints them out:
hn1 = (hex(random.randint(0,63))[2:])
hn2 = (hex(random.randint(0,255))[2:])
hn3 = (hex(random.randint(0,255))[2:])
Example Result: 37:bc:31
All is fine & dandy except when the hex number is from 0 through f. In that case the result may be 7b:5:5c
I'd actually like it to be 7b:05:5c
Is there a simple way of formatting this?
Don't convert the numbers to hex strings with hex(). Use print formatting to format the numbers.
>>> print '%02X:%02X:%02X' % (12, 21, 129)
>>> hx='%02X:%02X:%02X' % (12, 21,129)
>>> print hx
|All times are GMT -5. The time now is 03:08 PM.|