Hi there,
Quote:
Originally Posted by shygvy
Table creation fail.
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 5
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then you should look at the SQL statement that you're passing to the DBMS.
Code:
<?php
$name =$_POST["name"];
$position =$_POST["position"];
$visible =$_POST["visible"];
?>
This is PHP code and has nothing to do with the SQL error message.
By the way, it's nonsense to just copy the POST parameters. I've seen that a thousand times, but that doesn't make it any better.
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