How to use "for" modify my shell script
hi~
I have a shell script.but it's too large. How to use "for" modify this shell script. #!/bin/sh mono=`which mono` Release_DIR="/opt/Release" exe="${Release_DIR}/XXX.exe" ########### server2_DIR="/opt/server2" server3_DIR="/opt/server3" server4_DIR="/opt/server4" server5_DIR="/opt/server5" server6_DIR="/opt/server6" server7_DIR="/opt/server7" server8_DIR="/opt/server8" server9_DIR="/opt/server9" server10_DIR="/opt/server10" ########## s2=`netstat -ant|grep 0:5001|wc -l` s3=`netstat -ant|grep 0:5002|wc -l` s4=`netstat -ant|grep 0:5003|wc -l` s5=`netstat -ant|grep 0:5004|wc -l` s6=`netstat -ant|grep 0:5005|wc -l` s7=`netstat -ant|grep 0:5006|wc -l` s8=`netstat -ant|grep 0:5007|wc -l` s9=`netstat -ant|grep 0:5008|wc -l` s10=`netstat -ant|grep 0:5009|wc -l` ########## if [ -d ${server2_DIR} ]; then if [ $s2 -eq 0 ]; then screen -dmS S2 $mono $exe ${server2_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server3_DIR} ]; then if [ $s3 -eq 0 ]; then screen -dmS S3 $mono $exe ${server3_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server4_DIR} ]; then if [ $s4 -eq 0 ]; then screen -dmS S4 $mono $exe ${server4_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server5_DIR} ]; then if [ $s5 -eq 0 ]; then screen -dmS S5 $mono $exe ${server5_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server6_DIR} ]; then if [ $s6 -eq 0 ]; then screen -dmS S6 $mono $exe ${server6_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server7_DIR} ]; then if [ $s7 -eq 0 ]; then screen -dmS S7 $mono $exe ${server7_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server8_DIR} ]; then if [ $s8 -eq 0 ]; then screen -dmS S8 $mono $exe ${server8_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server9_DIR} ]; then if [ $s9 -eq 0 ]; then screen -dmS S9 $mono $exe ${server9_DIR}/ > /dev/null 2>&1;fi fi if [ -d ${server10_DIR} ]; then if [ $s10 -eq 0 ]; then screen -dmS S10 $mono $exe ${server10_DIR}/ > /dev/null 2>&1;fi fi |
Code:
for n in 2 3 4 5 6 7 8 9 10; do |
Thanks for replying.
It's working |
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