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mierdatuti

12-18-2008 11:01 AM

How to remove a value with sed

Hi,

I have this:

bash-2.03$ echo $pepe
hola adios kkk

I would like this:

pepe=adios kkk

I would like remove the first field of the pepe variable, but with a condition, I don't know the value of the fields.

I'm trying with sed but I can't:

bash-2.03$ echo $pepe | sed "s/.*\ $.*$.*$/var1=\1/"
var1=kkk

Could you say me how with sed?

Many thanks and sorry for my english!

fiomba

12-18-2008 12:06 PM

If the name of variable ($pepe) and its content

Code:

hola adios kkk

never change... the solution is trivial:

Code:

echo $pepe | sed "s/^hola /pepe=/"

The problem is tricker if the variable's name changes,
or you have a different content or word to substitute...,
for ex. you want to obtain...

Code:

pepe=adios kkk

pixellany

12-18-2008 02:28 PM

to operate on specific fields--where the content can vary---you are better off with something like AWK.

It CAN be done in SED.....You would have to write a Regex which matches the first group of characters that are NOT spaces, followed by a space. This seems to work, but is probably not the best solution:
sed 's/.[^ ]* //' filename
(The . is there to keep it from failing when there is a leading space.)

Really good tutorial on SED, AWK, and more here: http://www.grymoire.com/Unix/

PTrenholme

12-18-2008 05:36 PM

Is this what you want?

Code:

#!/bin/bash

pepe="hola adios xxx"

echo pepe = ${pepe}

declare pepe="$(echo $pepe | sed 's/.[^[:space:]]*[[:space:]]*\(.*$\)/\1/')"

echo pepe = ${pepe}

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