How to get the pattern using sed or awk?

ahpin · 08-02-2007, 02:58 AM

I would like to know how can i used the sed or awk to help me captured out the user name only from the file pattern as below:

/nfs/disk001/jeff
/nfs/disk002/mery
/nfs/homedisk01/kathie
/nfs/localhome/joseph
/nfs/disk02/catherine

The end result will be:
jeff
mery
kathie
joseph
catherine

Thanks.

colucix · 08-02-2007, 03:08 AM

Have you any experience in awk? Here you can define a field separator other than the blank space(s) and get the last field of each line, as in

Code:

gawk -F\/ '{print $NF}' dirlist

where dirlist is a file containing your input lines. Or in alternative you can simply pipe the input from another command to gawk.

jschiwal · 08-02-2007, 03:13 AM

sed 's#^.*/##' file

or

for line in $(cat testfile); do basename $line; done

ahpin · 08-02-2007, 03:16 AM

Brilliant!!!
Thanks for all your help....it is working now...real great.....