how to generate the intermediate files (i.e.,*.s, *.i ) in a different directory ?

rpittala · 05-13-2017, 01:22 PM

Okay !

Let me put it in this way:

Assume I am running the Makefile from the "/home" folder:

Code:

.c.o: 
        $(CC) -c -dg $< -o $@ \     -------> here I am compiling my /home/user/file1.c file with -dg option which generates file1.c.100.dg
        2>&1
        -$(MV) -f *.dg $(DEBUG_PATH)/ 2>/dev/null

So, the /home/user/file1.c executes and generates the ".o" file at /home/user/file1.o. But, the file1.c.100.dg file generates at "/home/" as /home/file1.c.100.dg along with some other files also

The above process continues for all the files file1.c,file2.c,...etc.

Now, I want to secure these *.c.100.dg files in a separate folder.

NevemTeve · 05-13-2017, 02:35 PM

Please check again the location of these files: you shouldn't be able to create files in /home/ only in /home/rpittala/

rpittala · 05-14-2017, 02:30 AM

Yeah !

That was just an example to understand the paths. Kindly, assume different locations.

pan64 · 05-14-2017, 03:59 AM

in post #1 you told

Quote:

it generates "*.c.100.dg" file at the current working directory

in post #16 you explained

Quote:

But, the file1.c.100.dg file generates at "/home/" as /home/file1.c.100.dg along with some other files also

would be nice to know exactly what's happening...

NevemTeve · 05-14-2017, 06:12 AM

> Kindly, assume different locations.

It doesn't work this way; you describe the actual situation, please.

MadeInGermany · 05-18-2017, 07:37 PM

Try a shell loop

Code:

for x in *.c.100.dg; do \
if [ -e "$x" ]; then \
$(MV) -f "$x" $(DEBUG_PATH) 2>/dev/null; \
fi \;
done

Maybe you'll need to escape $x as $$x