[SOLVED] How to access command line variables from awk

puth · 02-11-2010, 10:02 PM

hi,

I am taking an argument from the command prompt for my shell script ie $1 and i need to use $1 in my awk part of the script.But it actually doesn't get any value when used in awk.
Can anyone help me in accessing this command line argument in awk?

catkin · 02-11-2010, 10:11 PM

There are several ways of doing it. Can you post what you have tried? Then we can suggest how to make it work.

puth · 02-11-2010, 10:30 PM

I take domain name as the argument from the user and use it as $1.

domain=$1
In the awk statement i am using it as
if (match(toupper($0),"DOMAIN $domain")>0)
then perform some checks

DOMAIN $domain doesn't match to any text in my file and doesn't enter the loop.

ghostdog74 · 02-11-2010, 11:49 PM

use the -v option of awk.

catkin · 02-12-2010, 01:29 AM

Quote:

Originally Posted by puth

I take domain name as the argument from the user and use it as $1.

domain=$1
In the awk statement i am using it as
if (match(toupper($0),"DOMAIN $domain")>0)
then perform some checks

DOMAIN $domain doesn't match to any text in my file and doesn't enter the loop.

Please show the full awk statement within the script. It would be helpful if you put it in code tags (that's a link to instructions or you may prefer to use "Advanced Edit" mode which has a # button for code tags).

puth · 02-12-2010, 12:06 PM

i used

awk -v domain=${DOMAIN} ' BEGIN { dflag=0; }
if (match((toupper($0)),"DOMAIN "domain) > 0 ) and it worked.

Thanks.