I'm a little proud of myself because I made a compound interest chart without just using someone elses example, but combined several different ones program models. However, I'm a little bothered because when i run the program it won't show the first year without any interest. This is the code I made:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{

float total, $;
int years;

//$ is amount deposited in bank//
$=20;
years=0;

while(years <= 20){
total= $*pow(1 + .15, years);
printf("%d\t%.2f\n", years++, total);

}
}

im just confused because i modeled this off code for a Celsius/Fahrenheit table i got out of a book and that table shows zero degrees celecius when you run the program:

linclude <stdio.h>
/* pri~t Fahrenheit-Celsius table
for fahr = 0, 20, ..., 300; floatinq-point version */
maine )
{
float fahr, celsius;
int lower, upper, step;
lower = 0;
upper = 300;
step = 20;
/* lower limit of temperature table */
/*
upper limit */
/* step size */
fahr = lower;
while (fahr <= upper) {
celsius = (5.0/9.0) * (fahr-32.0);
printf("%3.0f %6.1f\n", fahr, celsius);
fahr = fahr + step;
}

I even tried running my compound interest chart with the upper, lower, and step functions in the exact same way this pdf book example is used, but the chart always starts with 1. How can i change my code to include year year with just 20 dollars in the bank account?

Thanks

Huh? I ran your code and the first line is

oh oops, stupid thread, i just forgot to try maximizing the screen

In the future, please use [code] tags to contain your code to make it more viewable.

DO NOT USE THE DOLLAR SIGN AS A VARIABLE NAME! You used "years", "fahr", a bunch of proper meaningful ones, and then that.

I'm glad you got your question answered, or rather it was already answered and you hadn't noticed.

Realize that you started by showing an interest compounding program, and segued into a temperature conversion program.