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DoME69

06-16-2015 08:12 AM

How can I echo " " depend on variable?

I'm using bash and I wanted to know how can I echo " " depend on variable?

For example:

Quote:

echo -e "\r[kuku $space]"

$space can be 1 or more space

Result will be depend on $space

Quote:

[kuku ]
[kuku . ]
[kuku .. ]
[kuku ... ]
[kuku .... ]...

* dots above should replaced by " " (space)

veerain

06-16-2015 08:18 AM

That could be done like this:

Code:

space="      "

echo -e "\r[kuku ${space}]"

genss

06-16-2015 08:22 AM

Code:

space="$space "

?

Edit:
Why does this butcher my caps ?
i want to use all caps for shell variables, forum

Habitual

06-16-2015 08:59 AM

Quote:

Originally Posted by genss (Post 5378023)

Code:

space="$space "

I never noticed, but

Code:

SPACE="SPACE "

was being converted to lower case.

Code:

[noparse]CAPS[/noparse]

preserves the case, but

Code:

[code]CAPS[/code]

didn't. Weird?

and after several previews, it seems to work?
More Coffee!

genss

06-16-2015 09:47 AM

@Habitual
i don't remember the forum doing this before
maybe its just me remembering wrong

edit: now it didn't convert them in CODE tags, or this line
im confused

anyway

@OP

Code:

#!/bin/bash

SPACE=""

for i in {1..5}

do

 echo "[kuku$SPACE]"

 SPACE="$SPACE "

done

something like this ?

rknichols

06-16-2015 10:58 AM

Or, just set Space to the longest string of spaces you expect to need, and then echo an appropriate substring:

Code:

Space="          "

for i in {1..5}; do

    echo "[kuku${Space:0:$i}]"

done

BTW, because of possible conflict with environment variable names, using all upper case for variables in non-system scripts is not recommended.

DoME69

06-17-2015 02:14 AM

Thanks :)

NevemTeve

06-17-2015 04:01 AM

I don't really get your question, but perhaps it is about padding. Use printf:

Code:

$ printf '[%*s]\n[%-*s]\n' 12 "kuku" 12 "kuku"

[        kuku]

[kuku        ]

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