Hoto run a for loop in C that depends on the program's first argument?

daYz · 01-08-2007, 10:49 AM

Hi,

I want to run a for loop, in C, that loops when the first expression of the for loop has an integer value that is less than the integer value given as the first argument to the program.

I have tried it like this:

Code:

for ( i = 0; i < argv[1]; i++)

But the loop is infinite this way.

So what is a proper way of doing this?

Thanks for the help.

traene · 01-08-2007, 11:29 AM

Are you trying to give an argument to your programme, which lets you give the number of loops, the programme should do? You can try something like:

Code:

    int loops=atoi(argv[1]);
    for ( i = 0; i < loops; i++)

However, you should check given parameters, and may provide a default value.

daYz · 01-08-2007, 11:43 AM

Hi traene,

Yes, it is exactly what I'm trying. I am not yet familiar with C++ and atoi seems to be part of that language. Can you show me how the same can be achieved by just using C?

Thanks

tuxdev · 01-08-2007, 11:55 AM

atoi is a part of C. try "man atoi" to see what you need to #include

daYz · 01-08-2007, 11:59 AM

Ok, I will take a look at atoi.

Thanks guys.