LinuxQuestions.org - Help with simple C string function

- Programming (https://www.linuxquestions.org/questions/programming-9/)

- - Help with simple C string function (https://www.linuxquestions.org/questions/programming-9/help-with-simple-c-string-function-4175418175/)

Help with simple C string function

Hi all

I have my main function as below :
I have included a couple of printfs. I need to know why the program never prints printf("1")even when the value of S is given as 0.

Thanks in advance

Code:

int main()

{

        int U, L, S, fahad;

        char in[20], *pEnd;

        node * root = (node *)calloc(1,sizeof(node));

        fgets(in, 20, stdin);

        U = strtol (in,&pEnd,10);

        L = strtol (pEnd,NULL,10);

        minSize = 1<<L;

        root->size = 1<<U;

        while(fgets(in, 20, stdin)>=0)

        {

                S = strtol (in,NULL,10);

                printf("\n S = %d\n",S);

                if(S == 0)

                {

                        printf("1");

                        deallocate(root, *in);

                        printf("2");

                }

                else

                        allocate(root, *in, S);

        }

        print(root);

        return 0;

}

Your program is incomplete; the first compilation error is:

Code:

bamba1.c:7: error: 'node' undeclared (first use in this function)

Add a '\n' at the end of the printf or (better?) force a flush of stdout.

I suspect there to be a crash in your deallocate() and therefore stdout does not get flushed and hence no output; might be wrong though.

if you want to see the complete source, see last post here: http://www.linuxquestions.org/questi...-c-4175417104/, probably up to date.
here is a small discussion about fflush: http://cboard.cprogramming.com/c-pro...sh-stdout.html

So it's indeed a crash in which case the problem is solved and the thread can be marked as such :)