LinuxQuestions.org - grepping last word of output

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grepping last word of output

Hi all,

I am trying to write a script in perl.
It executes df -h and reads the input :
/dev/sda7 688M 45M 608M 7% /scratch
/dev/sda3 981M 17M 915M 2% /tmp
/dev/sda8 494M 282M 187M 61% /usr/vice/cache
/dev/sda5 981M 69M 862M 8% /var

I want to get input in an array ,
where it contains only last field namely -> /scratch, /tmp, /usr/vice/cache, /var

@arr = <xyz>;
takes the whole line as input and I can parse it. But when partition names vary from machines to machines, that ofcourse is not a good idea.

Kindly suggest what to do ???

Regards,
Rajat Garg
SU

I beleive this should work for what you want:

Code:

#!/usr/bin/perl

@array=split(/\n/,`df`);

for ($done=1; $done<@array; $done++){

@fields=split(/\s/,$array[$done]);

$array[$done]=$fields[@fields-1];

print $array[$done]."\n";

}

exit;

you can start with

df | cut -c57-

df -h | awk '{ print $NF }'