grep ip adress using wildcards
 

Hi,

I need to grep a ip adress from the file mentioned below using wildcards.

The ip adresss can be like this,
10.211.32.3
192.168.1.1
132.213.231.312

the number of octets vaires for each..

-------------------------------

cat fileone

Keyboarders normally indent paragraphs three to five word spaces.based on what they were taught in school.while professionally printed material such as books and magazines generally use smaller indents.[citation needed] The Elements of Typographic Style states that "at least one 10.211.32.3 en [space]" should be used to indent paragraphs after the first,[6] noting that that is the "practical minimum".[7] An em space is the 192.168.1.1 most commonly used paragraph indent.[8] Miles Tinker, in his book Legibility of Print, concluded that indenting the first line of paragraphs increases readability by 7%, on the average.[9] 132.213.231.312

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So my task here is that, i need to get all the ip addresses in the above paragraph...

Thanks in advance..

Hi masterav,

assuming that all IPs are given in decimal, the following line should do the job:

grep -wo "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*" <filename>

See "man grep" for an explanation of -w and -o. The regular expression is a bit too tolerant (for example, it would also match "1000.0.0.0"), but that should not be a problem in practice.

Best regards
dmdeb

Thanks dmdeb
 

Dmdeb,

Simple and perfect..thats what i wanted,,,

Thanks you Dmdeb...:)