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Old 03-16-2012, 05:02 PM   #16
makyo
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Hi.

Here is a grep solution -- not so different from awk, but the initial fields need to be skipped explicitly:
Code:
#!/usr/bin/env bash

# @(#) s1	Demonstrate extraction of time-of-day between intervals.

pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
edges() { local _f _n _l;: ${1?"edges: need file"}; _f=$1;_l=$(wc -l $_f);
  head -${_n:=10} $_f ; pe "--- ( $_l: lines total )" ; tail -$_n $_f ; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C egrep

FILE=${1-data1}
pl " Sample of input file $FILE:"
head -14 $FILE

pl " Results, egrep:"
egrep '^(.* ){8}(09|1[0-6])' $FILE

exit 0
producing:
Code:
% ./s1

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian GNU/Linux 5.0.8 (lenny) 
bash GNU bash 3.2.39
egrep GNU grep 2.5.3

-----
 Sample of input file data1:
Tue Feb 21 08:55:04 EST 2012,Tue Feb 21 08:55:24 EST 2012,324.7,
Tue Feb 21 08:55:24 EST 2012,Tue Feb 21 08:55:44 EST 2012,356.65,
Tue Feb 21 08:55:44 EST 2012,Tue Feb 21 08:56:04 EST 2012,528.5,
Tue Feb 21 08:56:04 EST 2012,Tue Feb 21 08:56:24 EST 2012,489.2,
Tue Feb 21 08:56:24 EST 2012,Tue Feb 21 08:56:44 EST 2012,471.8,
Tue Feb 21 08:56:44 EST 2012,Tue Feb 21 08:57:04 EST 2012,281.6,
Tue Feb 21 08:57:04 EST 2012,Tue Feb 21 08:57:24 EST 2012,344.45,
Tue Feb 21 08:57:24 EST 2012,Tue Feb 21 08:58:04 EST 2012,430.05,
Tue Feb 21 08:58:04 EST 2012,Tue Feb 21 08:58:24 EST 2012,360.05,
Tue Feb 21 08:58:24 EST 2012,Tue Feb 21 08:58:44 EST 2012,384.75,
Tue Feb 21 08:58:44 EST 2012,Tue Feb 21 08:59:04 EST 2012,446.55,
Tue Feb 21 08:59:04 EST 2012,Tue Feb 21 08:59:24 EST 2012,312.4,
Tue Feb 21 08:59:24 EST 2012,Tue Feb 21 08:59:44 EST 2012,337.5,
Tue Feb 21 08:59:44 EST 2012,Tue Feb 21 09:00:04 EST 2012,379.45,

-----
 Results, egrep:
Tue Feb 21 08:59:44 EST 2012,Tue Feb 21 09:00:04 EST 2012,379.45,
Tue Feb 21 09:00:04 EST 2012,Tue Feb 21 09:00:24 EST 2012,1182.75,
Tue Feb 21 09:00:24 EST 2012,Tue Feb 21 09:00:44 EST 2012,1193.75,
Tue Feb 21 09:00:44 EST 2012,Tue Feb 21 09:01:04 EST 2012,768.55,
Tue Feb 21 09:01:04 EST 2012,Tue Feb 21 09:01:24 EST 2012,700.55,
Tue Feb 21 09:01:24 EST 2012,Tue Feb 21 09:01:44 EST 2012,814.7,
Tue Feb 21 09:01:44 EST 2012,Tue Feb 21 09:02:04 EST 2012,682.9,
Tue Feb 21 09:02:04 EST 2012,Tue Feb 21 09:02:24 EST 2012,585.3,
Tue Feb 21 09:02:24 EST 2012,Tue Feb 21 09:03:04 EST 2012,506.55,
Tue Feb 21 09:03:04 EST 2012,Tue Feb 21 09:03:24 EST 2012,393.95,
Tue Feb 21 09:03:24 EST 2012,Tue Feb 21 09:03:44 EST 2012,940.1,
Tue Feb 21 09:03:44 EST 2012,Tue Feb 21 09:04:04 EST 2012,994.5,
Tue Feb 21 09:04:04 EST 2012,Tue Feb 21 09:04:24 EST 2012,792.65,
Tue Feb 21 16:56:24 EST 2012,Tue Feb 21 16:56:44 EST 2012,90.65,
Tue Feb 21 16:56:44 EST 2012,Tue Feb 21 16:57:04 EST 2012,110.5,
Tue Feb 21 16:57:04 EST 2012,Tue Feb 21 16:57:44 EST 2012,120.0,
Tue Feb 21 16:57:44 EST 2012,Tue Feb 21 16:58:04 EST 2012,97.3,
Tue Feb 21 16:58:04 EST 2012,Tue Feb 21 16:58:24 EST 2012,116.45,
Tue Feb 21 16:58:24 EST 2012,Tue Feb 21 16:58:44 EST 2012,107.25,
Tue Feb 21 16:58:44 EST 2012,Tue Feb 21 16:59:24 EST 2012,94.45,
Tue Feb 21 16:59:24 EST 2012,Tue Feb 21 16:59:44 EST 2012,115.3,
Best wishes ... cheers, makyo
 
Old 03-17-2012, 02:54 PM   #17
danielbmartin
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Registered: Apr 2010
Location: Apex, NC, USA
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This gets a syntax error ...
Code:
awk '{if (8 < substr($9,1,2)) && (17 > substr($9,1,2)) {print $0}}'
... but I don't see why.

Daniel B. Martin
 
Old 03-18-2012, 01:44 AM   #18
firstfire
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Registered: Mar 2006
Location: Ekaterinburg, Russia
Distribution: Debian, Ubuntu
Posts: 709

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Hi.

Quote:
Originally Posted by danielbmartin View Post
This gets a syntax error ...
Code:
awk '{if (8 < substr($9,1,2)) && (17 > substr($9,1,2)) {print $0}}'
... but I don't see why.

Daniel B. Martin
You should put parantheses around the argument of if
Code:
awk '{if ( (8 < substr($9,1,2)) && (17 > substr($9,1,2)) ) {print $0}}'
 
1 members found this post helpful.
Old 03-19-2012, 01:55 PM   #19
danielbmartin
Senior Member
 
Registered: Apr 2010
Location: Apex, NC, USA
Distribution: Mint 17.3
Posts: 1,881

Rep: Reputation: 660Reputation: 660Reputation: 660Reputation: 660Reputation: 660Reputation: 660
Quote:
Originally Posted by firstfire View Post
You should put parantheses around the argument of if
Code:
awk '{if ( (8 < substr($9,1,2)) && (17 > substr($9,1,2)) ) {print $0}}'
Good, thank you, another perfect answer from firstfire.

Daniel B. Martin
 
  


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