[SOLVED] Gdb did not step into function when "step" typed!!!

915086731 · 06-19-2010, 07:51 AM

I typed "step", but gdb did not step into the specified function.

the code is:

Code:

#include "file.h"
#include "WordAnalyze.h"
#include "OperatorPriorAnalyze.h"
#include <cstring>
#include <iostream>

using namespace std;

int main(int argc, char** argv) {
    unsigned int size;
    char *mem;
    char* line;
    char tc[100];
    file f1;
    OperatorPriorAnalyze operator_analyze;
    WordAnalyze w1;
    size = f1.readfile("./test.txt", &mem );
    w1.setSource(mem);
    w1.setSize(size);
    while( !w1.atEnd() ){
	unsigned int i = w1.getLineSize();
	line = w1.getLine();                 //after "step" typed, gdb can step into getLine() function 
	operator_analyze.setSize(i);         //but gdb can not step into setSize(i) function 
	operator_analyze.setSource(line);    //gdb can't step into
	unsigned int k = 0;
	while(k<i){
	    tc[k] = line[k];
	    k++;
	}
	tc[k] = '\0';
	cout<< tc;
        operator_analyze.restart();
	if(operator_analyze.Judge() == 0 )
	    cout<< "Right！"  << endl;
	else
	    cout<< "Wrong！  " << operator_analyze.getError() << endl;
	delete line;
    }
    return 0;
}

It seems that gdb can't step into the function of "operator_analyze"class.
Can anyone explain to me?
Thanks !

graemef · 06-19-2010, 09:14 PM

Have you compiled the OperatorPriorAnalyze source with debugging information?
What do you mean by it "doesn't step into"?
What does the function do?

Remember an inlined function might not appear as you expect.

915086731 · 06-20-2010, 01:49 AM

Ｔhanks for your help. I am Chinese and my English is terrible!

All my source file were compiled with "-g" options.
When gdb stop at

Code:

operator_analyze.setSize(i);

, then I input "step", but gdb didn't come into the inner code of function

Code:

operator_analyze.setSize(i);

, gdb just executed the function like "next" .
If I run "stepi" many times, gdb can come into the body of

Code:

operator_analyze.setSize(i);

.

Ｄoes me explain clearly?

graemef · 06-20-2010, 02:13 AM

You English is fine.

Are any of these functions inline functions? In such a case the compiler will make a code substitution and so all of the inlined code will <b>be</b> on that one line, hence a step will just take you over.

Have you tried putting a breakpoint within the function you wanted to step into?

Do you have any compiler optimisation turned on?

915086731 · 06-23-2010, 09:44 AM

Thanks .
There is something wrong in my makefile. And the OperatorPriorAnalyz.cpp was not compiled with '-g' option. Sorry.