GCC problem

knockout · 04-28-2006, 05:00 AM

hey there
iam doing GCC cource ... i have found this problem

i have to output :

1
222
33333
4444444
555555555
using two for loops

i did like this :
#include <stdio.h>
int a,b
int main() {
for(a=1;a<6;a++){
for(b=1;b<=a;b++){
printf("%d\n",b);
}
printf("\n");
}
but i didnt get the output like above

}

perfect_circle · 04-28-2006, 05:33 AM

1. you have syntax errors forgot; and to close brankets
2. use the[code] tags like this to make your code readable

Code:

#include <stdio.h>
int main()
{
   printf("I'm main");
}

3. from LQ rules

Quote:

Do not expect LQ members to do your homework - you will learn much more by doing it yourself.

4. Try harder. It's really-really easy.

llmmix · 04-28-2006, 06:34 AM

#include <stdio.h>

int
main(void)
{
int a=0,b=0,c=0;

for(a=1; a<6; a++){
++c;
for(

)
printf("%d",c);
printf("\n");
}

return 0;
}

;-p

zulfilee · 04-28-2006, 06:38 AM

[HTML]3. from LQ rules

Quote:
Do not expect LQ members to do your homework - you will learn much more by doing it yourself.

4. Try harder. It's really-really easy.[/HTML]

Hey dont scare a newbie

You can use "splint" [ a tool that will probably be installed in your system] to check for syntax errors in your c file.

The syntax is simple

splint filename.c

Or try gcc with -Wall option

gcc -Wall filename.c

Cheers
Zulfi

graemef · 04-28-2006, 08:57 AM

Just remember that every statement in C needs to be terminated with a semicolon. If a statement is not properly terminated, the compiler normally only spots it when it reaches the next line. What this means is that warning messages often refer to the previous line.

I hope that helps. But if you are still unclear post your modified code and we can help you, we'll not do it but we will help.

cheers,

graeme.