gawk related issue

scbops · 08-17-2007, 03:52 AM

gawk related issue

ps aux |gawk ' { print $3,$2 }'

This command will print all the line, but I need to print first line only, anyone knows how to do that ?

slakmagik · 08-17-2007, 04:14 AM

ps aux |gawk 'NR == 1 { print $3,$2 }'

if you really want the first line, which is the header. Another way is just with 'head -1', of course - or 'head -n1' as some versions now seem to require.

slakmagik · 08-17-2007, 04:15 AM

oops - LQ went squirelly for a bit - sorry for the double post

scbops · 08-17-2007, 05:56 AM

Thankd you very much look like big brain
Appreciate if you can tell this also how I can display the last line

scbops · 08-17-2007, 06:02 AM

Thankd you very much look like big brain
Appreciate if you can tell this also how I can display the last line

schneidz · 08-17-2007, 10:14 AM

i hope your not married to awk:

this is not elegant but it gets the job done:

Code:

ps aux |gawk '{ print $3,$2 }' | head -n 1; ps aux |gawk '{ print $3,$2 }' | tail -n 1

ghostdog74 · 08-17-2007, 10:45 AM

well, theres no need to use so many pipes. you can get the header and last line using only 1 awk/gawk process.

Code:

ps aux |gawk 'NR==1{ print $3,$2 }{last=$3" "$2}END{print last}'