functions in PHP

gaddargarson · 10-06-2004, 04:34 AM

how can i get the variable which is the result of a function?
for example;

<?php
$number1=10;
$number2=20;
$number3=50;
function calc ($number1,$number2) {result1=$number1 * $number2;return $result1;}
function finalcalc ($result1,$number3) {result2=$result1 + $number3;return $result2;}
print calc( $number1,$number2);
print "<br>";
print finalcalc($result1,$number3);
?>

Why i can't see result2,although i see result1?
How can i get $result1 from the function?
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I have another question that how can i change the variables from browser(one by one or alltogether)?(especially in this example)

masand · 10-06-2004, 05:04 AM

hi there

try using

echo $result1

in ur function

regards

gamehack · 10-06-2004, 05:19 AM

PHP Code:



<?php 
$number1=10; 
$number2=20; 
$number3=50; 
function calc ($number1,$number2) {result1=$number1 * $number2;return $result1;} 
function finalcalc ($result1,$number3) {result2=$result1 + $number3;return $result2;} 
$result1 = calc( $number1,$number2); 
echo $result1; 
echo "<br>"; 
echo finalcalc($result1,$number3); 
?>

In the function calc, $result1 is not exported because it's a member variable of the functions, and the scope is only in the function body. And after the functions finished, it's automatically unset. So that code should do the thing.

Cheers,
gamehack

gaddargarson · 10-07-2004, 02:02 PM

thank you gamehack for your explanation

i understood the mistake.