[SOLVED] Find the text and copy to previous line

sunilsagar · 02-15-2012, 02:49 AM

Thanks a lot guys, it worked .. thanks so much ..

Reuti · 02-15-2012, 08:33 AM

@grail: did you use \0 by intention? It will put a null byte into the output, which is not printed but can be checked with the cat -A you mentioned.

grail · 02-15-2012, 09:24 AM

@reuti - the trinery in awk (?:) does not perform as expected if you use "" so the null gives you what we are after. Happy to know a different option

Reuti · 02-15-2012, 09:32 AM

Thx, but I’m still puzzled:

Code:

$ cat file
ADMU0508I: The Application Server "Portal" is STARTED
ADMU0508I: The Web server "HTTPServer" is STOPPED
ADMU0508I: The Node Agent "nodeagent" is STARTED
ADMU0508I: The Application Server "Server2" is
STARTED
ADMU0508I: The Application Server "Server3" is STOPPED
$ awk 'ORS=/ED$/?"\n":" \0"' file | cat -A
ADMU0508I: The Application Server "Portal" is STARTED$
ADMU0508I: The Web server "HTTPServer" is STOPPED$
ADMU0508I: The Node Agent "nodeagent" is STARTED$
ADMU0508I: The Application Server "Server2" is ^@STARTED$
ADMU0508I: The Application Server "Server3" is STOPPED$
$ awk 'ORS=/ED$/?"\n":" "' file | cat -A
ADMU0508I: The Application Server "Portal" is STARTED$
ADMU0508I: The Web server "HTTPServer" is STOPPED$
ADMU0508I: The Node Agent "nodeagent" is STARTED$
ADMU0508I: The Application Server "Server2" is STARTED$
ADMU0508I: The Application Server "Server3" is STOPPED$

There is a ^@ for me in the output. What should the \0 do?