[SOLVED] File selection in Python

devilboy09 · 01-25-2012, 08:02 AM

i want to create a file selector in python.here's my code, so far:

Code:

def file_open(self, widget):
                self.file_sel = gtk.FileSelection("File")
                self.file_sel.connect("destroy", lambda w:self.file_sel.destroy())
                self.file_sel.ok_button.connect("clicked", self.open_file)
                self.file_sel.cancel_button.connect("clicked", lambda w:self.file_sel.destroy())
                self.file_sel.show()

what's the body of "self.open_file" function. i can't figure it out.there's no function in FileSelection for opening a file

acid_kewpie · 01-25-2012, 08:22 AM

a file selection dialog shouldn't open a file, it should return the name of the chosen file for the rest of the code to act upon. you have the get_filename() method there to use. It's none of a gui widgets business actually DOING anything with the file.

note that FileSelection is obsolete, and I think you should be using FileChooserDialog instead these days if possible.

devilboy09 · 01-25-2012, 08:50 AM

i used this code as the body of self.open_file:

Code:

def open_file(self, w):
                filename = self.file_sel.get_filename()
                self.browser.open(filename)
                self.file_sel.destroy()

and it worked.you said i should use FileChooserDialog.is there any advantages for using this widget?

acid_kewpie · 01-25-2012, 12:25 PM

more modern I guess. I just read the API (the one you could have read

) and it said it was deprecated, so I repeated that.

devilboy09 · 01-25-2012, 01:21 PM

thamk you for your answers.i used File Chooser Dialog and it worked