Execution options in bash

eremit · 03-27-2005, 11:12 PM

Hi there,

just wondering how I can fetch execution options like this:

sh myscript -abcdef

With getopts I am only able to fetch options like this:

sh myscript -a sdlkf -b sdfkj - c slkfjsf

Anyone that understands my problem?

eremit

zeropash · 03-28-2005, 01:48 AM

giving an opstring of "abcdef" should solve your problem right?

eremit · 03-28-2005, 05:32 AM

Sorry if I didn't make myself clear enough, what I would like to do is to give several options where options a, b, c, d, e, f are all different options. In case of the order of the options:

sh myscript -abcdef

will have the same output as

-sh myscript -fedcba

And last; think I didn't really understand your reply zeropash: could you please try to reformulate it?

eremit

keefaz · 03-28-2005, 05:44 AM

The order does not matter, from what you say, I think your options don't take arguments...

Try :

Code:

#!/bin/bash

while getopts abcde option; do
    case $option in
        a) 
            echo "option: -a is set"
        ;;  
        b) 
            echo "option: -b is set"
        ;;  
        c) 
            echo "option: -c is set"
        ;;  
        d) 
            echo "option: -d is set"
        ;;  
        e) 
            echo "option: -e is set"
        ;;
    esac
done

And execute the script with any options order you want
./script -bdeac
./script -abcde
./script -cdeba
...

eremit · 03-28-2005, 09:40 PM

Yepp, this is what I was looking for

Thanks

eremit

lowpro2k3 · 03-28-2005, 09:58 PM

Just to throw my hat in the arena, if a flag (-a, -x, -y) requires an argument, follow it with a colon in your while loop. Example, out of -abcxyz flags, pretend '-b' and '-y' require an argument (-b foo; -y foo, etc..). The argument will be stored in $OPTARG (I believe for only one loop iteration). If an argument is recieved thats not in your argument list, your variable (in this case - $arguments) will recieve a question mark in it (and you can throw an error message from there.

Code:

while getopts ab:cxy:z arguments 2>/dev/null
do
  case $arguments in
    a) echo "-a set!";;
    b) echo "-b set with value $OPTARG";;
    c) echo "-c set!";;
    x) echo "-x set!";;
    y) echo "-y set with value $OPTARG";;
    z) echo "-z set!";;
   \?) echo "Usage: scriptname [ -a ] [ -b arg ] [ -c ] etc..."
  esac
done

lowpro2k3 · 03-28-2005, 10:00 PM

Quote:

Originally posted by keefaz
[B]The order does not matter, from what you say, I think your options don't take arguments...

Oops, didnt see that

Ah well, good to know for future reference anyways