Double and single quote, Question in expect

evilchild · 08-21-2004, 09:28 PM

I' m writing an expect script that is inside of a bash script and reads it's input from stdin, so I can define variables in the bash script that can be used in the expect script. But my problem is on the line

Code:

send "sudo useradd -c  '$NAME' -s /bin/sh -p '$PASS'  $USERNAME \r"

It returns an error because the $PASS variable contains an encrypted password,
which contains $'s which is reserved for expect variables, how can i quote this without receiving errors?

when this code is executed the command that runs actually looks like so

Code:

sudo useradd -c 'Tim Cook' -s /bin/sh -p '$2aHgs57dfdHdfsG3v' tim

Thanks Evilchild

jailbait · 08-22-2004, 02:12 PM

I am not certain that this will work but you could try escaping the '

send "sudo useradd -c '$NAME' -s /bin/sh -p \'$PASS\' $USERNAME \r"

-------------------------
Steve Stites

evilchild · 08-22-2004, 03:42 PM

no that still didn't work it tryed to execute, '
send "sudo useradd -c '$NAME' -s /bin/sh -p \'$PASS\' $USERNAME \r" ' and still got an error because of the encrypted pass .

Charalambos · 08-22-2004, 03:50 PM

{$PASS}

evilchild · 08-22-2004, 05:34 PM

for some reason '
send "sudo useradd -c '$NAME' -s /bin/sh -p {$PASS} $USERNAME \r" '
does not work for me, neither does
'
send "sudo useradd -c '$NAME' -s /bin/sh -p '{$PASS}' $USERNAME \r" '

or

'
send "sudo useradd -c '$NAME' -s /bin/sh -p {'$PASS'} $USERNAME \r" '