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Old 11-29-2005, 09:25 AM   #1
Gnarg
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Registered: Feb 2004
Location: Canada
Distribution: Gentoo Linux
Posts: 44

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Do I need something else when displaying a new dialog?


When my main dialog opens another dialog, do I need additional code to let the new dialog that is displayed to talk with the implementation class? Here is what I do to display a new dialog:
Code:
Form1 *frmMain;

frmMain = new Form1();
frmMain->show();

When the new dialog is shown I can't seem to have the dialog to use the implementation class. It still uses the class that QT generated.


My implementation class goes as follows:

Header File
Code:
class frmMainImpl : public Form1
{
       //more code here
}

Source File
Code:
frmMainImpl::frmMainImpl(QWidget *parent, const char *name) : Form1(parent, name)
{

}


Thanks...

Gnarg
 
Old 11-30-2005, 03:54 PM   #2
Mara
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Location: Grenoble
Distribution: Debian
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You create an instance of Form1 type, not frmMainImpl. I thin you should use rather the second class.
Code:
frmMainImpl *frmMain;

frmMain = new frmMainImpl();
frmMain->show();
This is a better idea, especially when you use Qt Designer to draw your widgets. When you use classes that inherit from the generated ones, you can edit in Qt Designer and make no modifications in your code (and not touch the generated classes at all).
 
Old 12-01-2005, 07:34 AM   #3
Gnarg
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Registered: Feb 2004
Location: Canada
Distribution: Gentoo Linux
Posts: 44

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Thanks Mara,

I looked over my code and done as you suggested and now it all works!


Thanks for your help on my misunderstanding....


Gnarg
 
  


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