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Old 03-30-2009, 05:35 PM   #1
pcock
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Registered: Sep 2004
Location: Sydney, Australia
Distribution: Archlinux
Posts: 16

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Smile [SOLVED] CSV null columns with gawk


Hi,

Suppose I have a file.
Code:
$ cat dat
1,newport  ,          ,5.38
2,sydnenham,     58894,2.12
How can I tell gawk to print column $1,$2 but if column $3 is blank to ignore spaces and output just ,, (with no spaces) else print values $3 $4

I tried something like this but I don't think it's right
Code:
#!/bin/bash
gawk 'BEGIN { FS=OFS=","}
{if  ($3 == "          ") print $1,$2,FS,$4 ; else print $1,$2,$3,$4}'
Thanks

Last edited by pcock; 03-30-2009 at 07:37 PM. Reason: resolved
 
Old 03-30-2009, 07:35 PM   #2
pcock
LQ Newbie
 
Registered: Sep 2004
Location: Sydney, Australia
Distribution: Archlinux
Posts: 16

Original Poster
Rep: Reputation: 0
Smile

It was easier to remove leading and trailing space between commas
Code:
sed 's;^ *;;;s; *, *;,;g;s; *$;;' a.txt > b.txt
found this here!
 
  


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