cretaing multiple directories based on file names

pkacker · 06-03-2009, 03:01 AM

I have around 95 files in a directory and i want to move them each in a separate directory. I want to put name of the directory same as their file name. for example in my directory file names are:

abc.pdb
bcd.pdb
cdf.pdb

i want to create the directories named (directories are not nested)

abc
bcd
cdf

and want to move above three files in the newly created folder.
I want to do this by using a shell script.

thanks

colucix · 06-03-2009, 03:12 AM

What have you tried so far? What does not work?

druuna · 06-03-2009, 03:17 AM

Hi,

Here's a one-liner that does what you want:

for THISFILE in `ls *pdb`; do DIRNAME=${THISFILE%%.*}; mkdir $DIRNAME; mv $THISFILE $DIRNAME; done

Up to you to figure out how this works and, if needed, make it into a script (I'm not sure if this is homework....)

ghostdog74 · 06-03-2009, 03:54 AM

Quote:

Originally Posted by druuna

Hi,

Here's a one-liner that does what you want:

for THISFILE in `ls *pdb`; do DIRNAME=${THISFILE%%.*}; mkdir $DIRNAME; mv $THISFILE $DIRNAME; done

no need ls..ls is useless here.

Code:

for THISFILE in *pdb

also, use % instead of %%, in case OP has files with more than 1 dot.

druuna · 06-03-2009, 03:57 AM

@ghostdog74: Both are good, valid points!

That's what happens if you're not really awake yet and are on auto-pilot

pkacker · 06-03-2009, 04:51 AM

Thanks for your suggestions.
I put my code like this:

#!/bin/bash

for THISFILE in *.pdb
do
DIRNAME=`echo $THISFILE | cut -d. -f1`
echo $DIRNAME
mkdir $DIRNAME
mv $THISFILE $DIRNAME
done

Thanks again

ghostdog74 · 06-03-2009, 05:07 AM

Quote:

Originally Posted by pkacker

Thanks for your suggestions.
I put my code like this:

#!/bin/bash
...
DIRNAME=`echo $THISFILE | cut -d. -f1`
..

Thanks again

don't need to call the cut command. just use what drunna posted

Code:

DIRNAME=${THISFILE%.*}