Create table with bash
 

hi all... how could I get a table that looks like this:

Variables:
one = 01 to 20 every 01
two = 12 to xx every 12 (this value keeps its increment of 12 every time the "one" variable increases by one in this case until the last value of "one" is reached)
three = 20 to 23 every 01

The table should look like this:
one two three
01 12 20
01 12 21
01 12 22
01 12 23
01 24 20
01 24 21
01 24 22
01 24 23
01 36 20
01 36 21
01 36 22
01 36 23
02 48 20
02 48 21
02 48 22
02 48 23
02 60 20
.. .. ..
20 xx 23

I think you can see the pattern!

I've been thinking over and over but no right answer came to my mind, I tried a triple for loop but could not get it to work.

Any hint would be appreciated!

Thanks!

The "table" is easy; I'll assume you know how to print stuff to a shell.

For maths part, look into the `bc` command or else just variable incrementing.

You'll probably want to use nested `while` loops.

Hope that helps.

thanks, do you have any idea how to declare a variable resulted from arithmetic operatio inside an array variable?

for example

array=($var $var+12 $var+24 $var+36)

You want to print this, or put it into a variable? If the former then it is three nested cycle and one printf

ok thanks i will try tomorrow morning and put the code here if i get stuck again at some point

I would add that your explanation of the fields does not follow your example data!

If we ignore column 2 for the moment, even though columns 1 and 3 start with different numbers your incremental information was the same:

one = 01 to 20 every 01
three = 20 to 23 every 01

Yet your example shows:
Here we can clearly see column three increasing by 1 each time until the threshold of 23 is reached, yet column one has not increased at all for any of the 8 rows shown.

So either you need to provide a better explanation or your current example needs to be altered.

column 2 has values greater than 36 in your example

Thanks for pointing out my mistake grail and keefaz, I just modified the original post, In fact the problem is that every time the variable "one" increments i want to keep the variable "two" increasing by 12 until the last value of "one" is reached

Im creating a little script, in a few minutes i will post it so you can see where I have the problem!

If I understood correctly, this following bash script should generate the table as you requested:

Thanks a lot gda! it works!

gda's code
Your example
Not the same. Can you post what you came up with yet?

The example is still confusing, why the value 56 on column two?

column 1 is incremented by one after column 2 has incremented by 12 two times, correct?

Think about how nested loops work. The only thing different about column 2 is that it always is incremented by 12.

My code should be consistent with that!
Anyway you are right the example table is not consistent with these requirements. So I supposed the table was wrong. Is my interpretation correct?

Yes, but without knowing the relationship between one,two and three there are many possibilities.

Only the OP knows...