Counting the number of exit variables

0bfuscated · 07-01-2010, 06:54 PM

Is there a way to count the number of errors- an exit variable $? from one function?

precat1 ()
{
grep -i $CODE $TEST
if [ "$?" -eq "1" ]; then
echo "Warning, no response. 1" >> $MSG
mail -s"$SUB" "$TO" < $MSG
fi

grep -i $CODE $TEST
if [ "$?" -eq "1" ]; then
echo "Warning, no response. 1" >> $MSG
mail -s"$SUB" "$TO" < $MSG
fi

grep -i $CODE $TEST
if [ "$?" -eq "1" ]; then
echo "Warning, no response. 1" >> $MSG
mail -s"$SUB" "$TO" < $MSG
fi

grep -i $CODE $TEST
if [ "$?" -eq "1" ]; then
echo "Warning, no response. 1" >> $MSG
mail -s"$SUB" "$TO" < $MSG
fi

}

the output from the exit variable (either erroneous or correct (1) or (0)) is it possible to add the erroneous one ups?

-Thanks in Advance.

jlinkels · 07-01-2010, 07:40 PM

You can use any exit integer exit code < 256. It is not limited to 0 or 1. You check the exit code in the caller code using $?

jlinkels

KenJackson · 07-01-2010, 08:52 PM

Code:

#/bin/bash
total=0
for n in 1 2 3 4 5; do
    false
    ((total += $?))
done
echo $total

The output is 5.
Is that what you mean?

0bfuscated · 07-02-2010, 11:43 AM

Quote:

Originally Posted by KenJackson

Code:

#/bin/bash
total=0
for n in 1 2 3 4 5; do
    false
    ((total += $?))
done
echo $total

The output is 5.
Is that what you mean?

I did something similar:
TEST6=$(($TEST1 + $TEST2 + $TEST3 + $TEST4 + $TEST5))
if [ "5" -eq "$TEST6" ]; then
func2
else
exit 0
fi

I appreciate the replied. I had a typical blank-out moment worth posting about.

-Take Care!