Converting int value to char

liguorir · 05-22-2004, 04:33 PM

I need some advise on rand.

rkef · 05-22-2004, 06:13 PM

I'm not familiar with rand() and I'm not on a machine where I can test what you've written (it looks needlessly complicated to me, but I could be missing something), but assuming the expression on the rhs of the sum operator generates a number between zero and 25, what you've got is a perfectly valid char and you may assign it as such (a char being a byte-wide value on my machine, anyway; 0-255).

Also, for readability you could change 97 to 'a'. Hard-coding sucks!

itsme86 · 05-22-2004, 09:06 PM

char_name[0] = (char)( 97+(int) (25.0*rand()/(RAND_MAX+1.0)) );

The_Nerd · 05-22-2004, 09:12 PM

I think he means a string???

Like so if you mean an int-string value:

sprintf(char_name, "%d", ( 97+(int) (25.0*rand()/(RAND_MAX+1.0)) ));

itsme86 · 05-23-2004, 12:30 AM

Quote:

Originally posted by The_Nerd
I think he means a string???

Like so if you mean an int-string value:

sprintf(char_name, "%d", ( 97+(int) (25.0*rand()/(RAND_MAX+1.0)) ));

He wants it to show up as a character I think...he doesn't want a string that prints out as, for example, "105".

If he wants a string then just add char_name[1] = '\0'; to my previous example or use %c instead of %d in The_Nerd's example.

liguorir · 05-23-2004, 03:54 AM

Thanks for the advise

itsme86 · 05-23-2004, 08:30 AM

You'll want to change declaration for salt to char salt[3]; and after your for() loop add salt[2] = '\0';. Otherwise you'll get the occasional segfault.

liguorir · 05-23-2004, 06:39 PM

I made your suggested change, but why exactly why does it occassionally fault?

itsme86 · 05-23-2004, 07:21 PM

It segfaults because it's not a real string unless it's NUL-terminated. All string functions know that the end of the string will be a NUL-terminator. If it's not present, then your string had 2 valid chars and then garbage after it. String functions would keep on scanning right through the garbage and cause all sorts of junk to happen