Check type of input from user

leprechaun3 · 08-17-2016, 01:26 PM

I'm making a small program for learning purposes. The user is asked to input numbers into a few entry boxes, but I would like for the program to give focus to the box that does not contain an appropriate value. I already have it print an error message to the user from ValueError, but this is just in the event that any of the boxes does not contain an appropriate number (I used an if statement to check for entry boxes that contain a 0 or negative when they should only have a positive number since those would not be caught by ValueError). So after it prints the error message I want it to figure out which box is the problem and give that box focus. I found a suggestion for using

Code:

if not v.get():

which works if the box is empty, but does not work if the box contains a non-number (though it still prints the error message). Ideas on how to get around this?

An earlier iteration of the program is already posted here

leprechaun3 · 08-22-2016, 12:48 AM

Well I have found a way to make it work, but it does not seem very clean or efficient. So if anyone has ideas on how to clean this up it would be appreciated.

Code:

...
except ValueError:
   if not v.get(): #Is there a way for me to group this in with the next if statement?
      v_error()
   else:
      v2 = ord(v.get())
      if not 47 < v2 < 58: #this excludes the numeric characters in case the exception was caused by a different box
         v_error() #Calls a separate function so I only have to write each error message and the commands to go with it once
      elif not w.get():
         w_error()
      else:
         w2 = ord(w.get())
         if not 47 < w2 < 58:
             w_error()
         elif not x.get():
             x_error()
         else:
             x2 = ord(x.get())
             if not 47 < x2 < 58:
                 x_error()

Again, I just feel like there must be something cleaner than this