I have this very simple piece of C code.

--------------------------------------
#include<stdio.h>
#include<stdlib.h>
#include<string.h>

char x[]="hello";
char *xx[] = {"hello","there"};

int main()
{
printf("%c\n",xx[0][0]);
x[0]='a'; /* this can be done */
xx[0][0]='x'; /* this fails!!! segfault will occur, but WHY */
return(0);
}
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Compile with gcc and run it.
As you can see, it will segfault. You can change a value in the character value of variable x, but not in xx.

I don't get that!?

What could I do to be able to change values in the initialized variable xx.

Thanks!

well.. im a little drunk but im pretty sure that when you say
you are declaring an array of literals..

cant change a literal..

Drunk or not xhi is correct , see this thread

You want to make xx an array of arrays.