can awk see bash script arguments ?

sharapchi · 12-14-2006, 02:47 PM

For example i want to write a script names "example.sh". I want to pass any arguments to this script. How can i use this argument for example "$1" in awk?

awk "{print $1}" #?

thanks

acid_kewpie · 12-14-2006, 03:10 PM

you need to pass it through to awk using the -v option, e.g.

Code:

awk -v awkvarname=$BASHVARIABLE "{print £0.51 (awkvarname)}"

sharapchi · 12-14-2006, 03:48 PM

For example we have a sentence in a file like "word1 word2 word3 word4." We can get columbs with 'awk "{print $1 $2}"' command. Now i want to write a bash script that gets specified word from sentence. We suppose that the sentence is in the file named "file".

bash> ./example.sh file 3

this command should write the third word.

#this is example.sh

awk "{print $2}" #?

acid_kewpie · 12-14-2006, 04:21 PM

that example appears to make very little sense, but i still think you're after the kind of thing i'm suggesting... maybe.

Tinkster · 12-14-2006, 05:31 PM

Quote:

Originally Posted by sharapchi

For example we have a sentence in a file like "word1 word2 word3 word4." We can get columbs with 'awk "{print $1 $2}"' command. Now i want to write a bash script that gets specified word from sentence. We suppose that the sentence is in the file named "file".

bash> ./example.sh file 3

this command should write the third word.

#this is example.sh

awk "{print $2}" #?

Code:

#!/bin/bash
awk -v number=$2 '{print $number}' $1

Something like that?

Cheers,
Tink

sharapchi · 12-14-2006, 07:23 PM

It did not worked.

awk -v awkarg=$2 "{ print $awkarg }" $1

this writes all contents of the file given with $1.

matthewg42 · 12-14-2006, 07:48 PM

use 'single quotes', not "double quotes". The double quotes allow the shell to expand the value of $awkarg before awk sees it, which gives you the wrong result. awk must see the $awkark as a literal string.

sharapchi · 12-14-2006, 08:03 PM

what a mistake.. Thanks for all.