LinuxQuestions.org - [SOLVED] C: Segmentation fault when freeing allocated 2D array

Dear all,

I know that seems to be a common question, but information from the web does not help me.
So problem is in the title.

Here is what I do:

First I declare the pointers.

Code:

double **rijx,**rijy,**rijz;

Then I allocate the require memory.

Code:

  rijx = malloc (atom_number*sizeof(double*));

  rijy = malloc (atom_number*sizeof(double*));

  rijz = malloc (atom_number*sizeof(double*));

  if ( (rijx == NULL) || (rijy == NULL) || (rijz == NULL) ){ (void)fprintf(stdout,"compute_energy_cuda_: failed to allocate rijx or rijy or rijz\n");exit (EXIT_FAILURE);}                          

  for (i=0;i<=atom_number-1;i++) {

        rijx[i] = malloc (atom_number*sizeof(double));

        rijy[i] = malloc (atom_number*sizeof(double));      

        rijz[i] = malloc (atom_number*sizeof(double));

        if ( (rijx[i] == NULL) || (rijy[i] == NULL) || (rijz[i] == NULL) ){ (void)fprintf(stdout,"compute_energy_cuda_: failed to allocate rijx[%d] or rijy[%d] or rijz[%d]\n",i,i,i);exit (EXIT_FAILURE);}

                                }

Then I initialize the arrays ....

Code:



  for (i=0;i<=atom_number-1;i++) {

    for (j=0;j<=atom_number-1;j++) {

      rijx[i][j] = 0.0;

      rijy[i][j] = 0.0;

      rijz[i][j] = 0.0;

                                  }

                                }

I do some stuff with them ...

Then I free the memory by doing

Code:

  for (i=0;i<=atom_number-1;i++) {

        (void)free(rijx[i]);

        (void)free(rijy[i]);        

        (void)free(rijz[i]);

                                }

and in crash during this step.
I do not see what's going wrong here.
Then I do this

Code:

(void)free(rijx);(void)free(rijy);(void)free(rijz);

But it does not get to here so far.

So, some hints are more than welcome.
Thanks in advance,

Éric.