[SOLVED] C++, constructor overloading

Netooo · 05-25-2012, 08:46 AM

If I have more than one constructor in a class, how do I know wich of them is the default one?

dugan · 05-25-2012, 08:50 AM

Aren't "the constructor that doesn't take any parameters" and "the default constructor" synonymous?

Netooo · 05-25-2012, 08:51 AM

Quote:

Originally Posted by dugan

Aren't "the constructor that doesn't take any parameters" and "the default constructor" synonymous?

I don't know, are they? =/

Nylex · 05-25-2012, 09:31 AM

Yes, dugan is correct. If you supply any constructor with arguments, the compiler will not supply a default constructor. If you need one, you'll have to provide it. For example, consider the following simple class:

Code:

class Foo
{
  public:
    Foo(int val):x(val) {}

  private:
    int x;
};

The following statement will not compile, as there is no default constructor:

Code:

Foo f;

In this case, you need to add explicitly a no argument constructor to your class definition.

Netooo · 05-26-2012, 08:34 AM

Thanks guys, that's what I needed to know.