| snowman81 |
08-24-2017 09:34 PM |
Best/Easiest way to implement a Python script as a webpage?
I have a Python script that takes an encoded URL from Proofpoint and decodes it. You call it with the encoded URL as an argument. I want to be able to have a very simple webpage on a server that just has an input box for the URL and underneath is the decoded output. I'm thinking of trying to implement it with Nginx+FastCGI maybe? Are there easier ways to do this as a non-coder? Thanks.
Code:
#!python
import sys
import re
import urllib.parse
import html.parser
def main():
rewrittenurl = sys.argv[1]
match = re.search(r'https://urldefense.proofpoint.com/(v[0-9])/', rewrittenurl)
if match:
if match.group(1) == 'v1':
decodev1(rewrittenurl)
elif match.group(1) == 'v2':
decodev2(rewrittenurl)
else:
print('Unrecognized version in: ', rewrittenurl)
else:
print('No valid URL found in input: ', rewrittenurl)
def decodev1 (rewrittenurl):
match = re.search(r'u=(.+?)&k=',rewrittenurl)
if match:
urlencodedurl = match.group(1)
htmlencodedurl = urllib.parse.unquote(urlencodedurl)
url = html.parser.HTMLParser().unescape(htmlencodedurl)
print(url)
else:
print('Error parsing URL')
def decodev2 (rewrittenurl):
match = re.search(r'u=(.+?)&[dc]=',rewrittenurl)
if match:
specialencodedurl = match.group(1)
trans = str.maketrans('-_', '%/')
urlencodedurl = specialencodedurl.translate(trans)
htmlencodedurl = urllib.parse.unquote(urlencodedurl)
url = html.parser.HTMLParser().unescape(htmlencodedurl)
print(url)
else:
print('Error parsing URL')
if __name__ == '__main__':
main()
|
