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Old 06-01-2006, 09:11 AM   #1
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bash variable loses contents in mysql statement

I have a variable $id that contains an id

I can echo it without any problem but...

as soon as I do this
`$mysql "insert into webusers_db(webuserid,db) values('"${id}"','"${db}"')"`

the db gets entered but the id is the default value in my table of zero
I have tried '$id' '"$id"' '"${id}"' '"[${id}]"' '"["${id}"]"' nothing seems to work
Old 06-01-2006, 10:11 AM   #2
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it's the single quotes, try this:

`$mysql "insert into webusers_db(webuserid,db) values(\'${id}\',\'${db}\')"`
Old 06-01-2006, 10:18 AM   #3
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alright what I got when I escaped the single 's
ERROR at line 1: Unknown command '\''.

/me scratches his head
Old 06-02-2006, 04:15 AM   #4
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This should work:
$mysql "insert into webusers_db(webuserid,db) values('${id}','${db}')"
Quoting and escaping is not allways useful or needed


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