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Old 05-27-2008, 07:17 AM   #1
B-Boy
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Registered: Jan 2008
Posts: 103

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Bash Scripting


Hi everyone

I am a newbie to Linux and scripting anyway I want to write a script that will put the contents on a file1 into a variable1 and the contents of file2 into a variable2 then if they are the same a command must run eg xeyes else they do not match...something like that


here is my script please dont laugh ;-)
Code:
 #!/bin/bash
LOG= cat /path/file1
LOG1= cat /path/file2
            if [ "$LOG" = "$LOG2" ]; then
                xeyes
            else
                 echo they do not match
            fi
 
Old 05-27-2008, 07:39 AM   #2
pwc101
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Registered: Oct 2005
Location: UK
Distribution: Slackware
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You need to use either backticks (` - not an apostrophe: ') or the $() construct to evaluate the cat /path/file? commands:
Code:
LOG=$(cat /path/file1)
LOG1=$(cat /path/file2)
I prefer $() as it's more readable and you can nest them more easily.

I addition, to get the contents of a file into a variable, there's no need to use an external program (cat). You can simply use standard input:
Code:
LOG=$(< /path/file1)
The rest of the code should work ok.
 
Old 05-28-2008, 01:15 AM   #3
B-Boy
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Registered: Jan 2008
Posts: 103

Original Poster
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Smile

Quote:
Originally Posted by pwc101 View Post
You need to use either backticks (` - not an apostrophe: ') or the $() construct to evaluate the cat /path/file? commands:
Code:
LOG=$(cat /path/file1)
LOG1=$(cat /path/file2)
I prefer $() as it's more readable and you can nest them more easily.

I addition, to get the contents of a file into a variable, there's no need to use an external program (cat). You can simply use standard input:
Code:
LOG=$(< /path/file1)
The rest of the code should work ok.
thinks for your help it worked
 
  


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