LinuxQuestions.org - bash script to replace char in variable

- Programming (https://www.linuxquestions.org/questions/programming-9/)

- - bash script to replace char in variable (https://www.linuxquestions.org/questions/programming-9/bash-script-to-replace-char-in-variable-251992/)

bash script to replace char in variable

I have a variable $ipath that contains a path "/usr/local" which I need to convert to "_usr_local"

I built the following at the shell prompt to do this

Code:

export tpath=`echo $ipath | sed -e 's/\//_/g'`

That worked.

Now I need to move it into a script so I dropped the export and tried:

Code:

for ipath in $backupdirs

#replace slashes with underscores

tpath=`echo $ipath| sed -e 's/\//_/g'`

I get an error:
line 30: syntax error near unexpected token `tpath=`echo $ipath| sed -e 's/\//_/g'`'

Can you help me fix this or suggest a better approach?

I hate answering my own posts. Problem was I added the sed code between the 'for' and the 'do'. Moving it to after the 'do' worked.

Sorry

This _should_ work...

Code:

do

#replace slashes with underscores

  tpath=$(echo $ipath | sed -e 's/\//_/g')

  echo $tpath

done

tpath=`echo -e ${ipath//:/\_}`

HTH :)

<EDIT> Oops...

tpath=`echo ${ipath//\//_}`

Thanks, folks - problem solved AND I learned something