Hi .. I am a new bie in writing scripts, so this doubt may be a simple one.

I am trying to apply a parsing program to a set of input files in a directoy.
How can i access all the files from a source directory , one by one and to write the
output files with another name to some directory ? i.e
my exe file is a.out
I have input files 1.txt,2.txt .. in one directory.
I need this cmd line ./a.out <inputfilename> > <outputfilename> , on all input files.

can i write a loop to get all files like this ? right now i am writing the same line
again and again to apply to all files..

Plz post ur suggestions.

Thank u

Shinni

Hi,
You can use a loop as follows. The problem is with naming the output file. I have made the output filename as inpufilename.out

#!/bin/bash
cd <input_file_directory>
for file in `dir -d *` ; do
<exeFile with full path> "$file" <output_file_path/"$file".out>
done

HTH.

Thanks a lot .. It is working..

I have another doubt , as a follow up to the same script .. If i need to change this input directory and output directory to test different data sets, what should i do ? Now, i hav specified SourceDir and DestDir within the program. Can i pass command line arguements or do something similar to assign some path to variables representing the directories , each time when i run the script?

Thank u

Shinni

Pass the input and output path as argument to the script.

#!/bin/bash
input_file-directory=$1
output_file_path=$2
cd <input_file_directory>

for file in `dir -d *` ; do
<exeFile with full path> "$file" <output_file_path/"$file".out>
done

I also recomend you to go through any shell script tutorials. I find one by "Mendel cooper" to be interesting.

HTH.

This could be a job for make.
You don't want to regenerate every time if the
data hasn't changed. (do you?)


the indents are TABs.
copy to file called Makefile
then type make.

or maybe not?

thanks. works perfectly