bash script deleting rows
 

Hi all, I have to create a bash script doing the following: ask in input a string, find that string into a file, then delete the all rows containing that string. Someone can kindly help me? I'm not so expert in scripting, I know linux commands.

Is this a homework? What have you tried so far? If you know linux commands then you should be able to solve the problem.

Google the following:

"bash read"
or
"positional parameters"
and
"sed"

grep and sed are good ones, maybe just sed for the find and delete part. post what you come up with.

input is easy,
from groogle search

#!/bin/bash
# This script will test if you have given a leap year or not.

echo "Type the year that you want to check (4 digits), followed by [ENTER]:"

read year