Bash sciprt question, how to do this????

yulitao · 03-23-2004, 08:27 PM

This is my script

DATE=`/bin/date`
NEW_USERS="/script/userlist"
HOME_BASE="/home/"

cat ${NEW_USERS} | \
while read USER PASSWORD GROUP FULLNAME
do
if [ -z "`grep ^${GROUP}: /etc/group`" ];then
groupadd ${GROUP}
echo "Group ${GROUP} successfully added."
fi
if [ -z "`grep ^${USER}: /etc/passwd`" ]
then
useradd -g ${GROUP} -p ${PASSWORD} -c ${FULLNAME} -m -d ${HOME_BASE}${USER} ${USER}

echo "User ${USER} successfully added."
else
echo "The user has existed"

fi

everything is working fine, now the format of userlist is
USER PASSWORD GROUP FULLNAME
john01 mypass business JOHN

So if I just want to username has no more than 6 characters, password must be over 8 characters, Group just can be "business" or "operation" or "marketing", otherwise the user information is invalid and can't be allowed to add in linux system, and shows "user invaild"information. but now even I input username like john23323e2323403222332, it still be added, so how should I do! Please!

Looking_Lost · 03-24-2004, 09:05 AM

You can get the length of a variable using this format

${#MYVARIABLE}

so I guess you could do

Code:

#!/bin/bash

USERNAME="john123456789"

if [ ${#USERNAME} -gt 6 ]; then
  echo "UserName is too long"
else
  echo "Okay, Length of USERNAME is ${#USERNAME}"
fi

I'd test for zero length aswell just incase