bash - question about grepping a specific time period
I am fairly new to bash and have a question how I can accomplish the following:
I have to grep in a logfile for a specific time period and print it out.
For example: someone wants to get all results from a logfile from 21:05-21:10
How do print/grep that period?
An example begin of a log entry: 2010-08-04 00:00:01,774 ERROR
Thanks for any help.