Bash: how to test for a number in Array within if loop?
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if [ $temp = 1 ]
printf "temp = 1";
printf "temp = 0";
/END of myscript.sh------------------------------------------------
Q2) I like to avoid writing to file.txt file for speed purpos. How would I redirect output of the first command from myscript.sh to an array and use that array for testing in if construct.
Please note, that I am not just testing for occurence of a single number (namely 34) only. It is just a test. There is a while-do-done loop around the if construct that delivers different variables to be tested again their appearence in the file.txt.
Hope I could explain my problem. If something is not clear, please ask. I'd greatly appreciate your ideas.
# findnum.sh by int0x80
# check if any numbers in the list exist in file
numbers="34 99 152 293 347";
for n in $numbers; do
echo -n "$n? ";
if ! grep -q "^$n\$" $1
int0x80:~/source/bash/fileio$ ./findnum.sh numbers.txt