Bash: how to test for a number in Array within if loop?

realos · 12-15-2006, 06:22 AM

---------------------------file.txt-----------------------------------
0
34
71
77
152
159
163
293
/END file.txt-------------------------------------------------------

I like to define an if loop with two possible branches depending on whether an integer is found in the error_block.txt file or not.

if [integer in file.txt]
then
command1;
else
command2;
fi

Following is my try at solving this problem but it does not work.

--------------------------------- myscript.sh----------------------------
/skipping

grep '^error' tracefile.txt | awk '{print $3}' > file.txt;

temp='cat file.txt | mawk '/34/{++count}END{print count}''

if [ $temp = 1 ]
then
printf "temp = 1";
else
printf "temp = 0";
fi

/END of myscript.sh------------------------------------------------

Q2) I like to avoid writing to file.txt file for speed purpos. How would I redirect output of the first command from myscript.sh to an array and use that array for testing in if construct.

Please note, that I am not just testing for occurence of a single number (namely 34) only. It is just a test. There is a while-do-done loop around the if construct that delivers different variables to be tested again their appearence in the file.txt.

Hope I could explain my problem. If something is not clear, please ask. I'd greatly appreciate your ideas.

Regards,

int0x80 · 12-15-2006, 07:59 AM

Bash script:

Code:

#!/bin/bash
# findnum.sh by int0x80
# check if any numbers in the list exist in file

numbers="34 99 152 293 347";
for n in $numbers; do
    echo -n "$n?    ";
    if ! grep -q "^$n\$" $1
    then
        echo "No";
    else
        echo "Yes";
    fi
done

Usage:

Code:

int0x80:~/source/bash/fileio$ ./findnum.sh numbers.txt
34?     Yes
99?     No
152?    Yes
293?    Yes
347?    No

The numbers.txt file:

Code:

int0x80:~/source/bash/fileio$ cat numbers.txt
0
34
71
77
152
159
163
293