bash dilema

mad_penguin · 06-23-2010, 07:05 PM

Hi !

I'm planing to write a bash script that will make some web stats reports and I'm stuck on beginning because I don't know how can I read a directory content, put everything in a variable, compare the variable value with current date and go further.

More specific ...

I have /var/apache/log/. Here I have access logs on date ( like access.log.24.06.2010.gz and so on ).

How can I do to automatically zgrep (in a bash script) last day .gz ??

I look forward for your suggestions.

Thanks a lot.

pixellany · 06-23-2010, 07:11 PM

I think you will need to give us some more information---including a sample of what the data (filenames?) looks like.

Quote:

...zgrep (in a bash script) last day .gz

What does this mean?

mad_penguin · 06-23-2010, 07:20 PM

For each day I have a archive that looks like download.2010-06-23.site.access.gz . I wish to read from another file, let say 'url_list' where I should have the url's I wish to zgrep and run the command for each URL in the $url_list but for the .gz file created one day behind.

Thanks!

grail · 06-23-2010, 07:43 PM

Well here is a lead into how you 'could' get the last file:

Code:

ls -lrt /var/apache/log/ | tail -n1 | awk '{print $NF}'