[SOLVED] Bash concatenating string to variable

abercrombieande · 01-18-2011, 03:18 PM

I have a program that loops over each word in a sentence. I need to append a constant to the beginning and end of each word. It works up until the last word on the line. I am stumped. Thanks for any suggestions

Code:

  for w in $(echo $i | tr "," "\n")
        do    
         echo $w  
         w='a'$w'a'
         echo  $w
        done

Output:
2011-18-01
a2011-18-01a
40
a40a
A
aAa
DWELLING
aDWELLING

Snark1994 · 01-18-2011, 03:34 PM

What are you giving it as $i?

Code:

#!/bin/bash

i="2011-18-01 40 A DWELLING"
for w in $(echo $i | tr "," "\n")
do    
   w='a'$w'a'
   echo  $w
done

works for me, printing

Code:

a2011-18-01a
a40a
aAa
aDWELLINGa

Kenhelm · 01-18-2011, 03:57 PM

If the text was edited in Windows there could be a carriage return character at the end of each line.
\n is the end of line code for Linux
\r\n is the end of line code for Windows
\n represents a newline character
\r represents a carriage return character

Code:

w=DWELLING$'\r'        # $'\r' creates a carriage return in bash
echo $w
w='a'$w'b'
echo  $w
echo  $w | tr -d '\r'  # tr can delete carriage returns

DWELLING
bDWELLING
aDWELLINGb

kurumi · 01-18-2011, 11:27 PM

Code:

# echo "2011-18-01 40 A DWELLING"  | ruby -e 'puts gets.split().map{|x|"a"+x}'
a2011-18-01
a40
aA
aDWELLING

abercrombieande · 01-19-2011, 07:04 AM

Quote:

Originally Posted by Kenhelm

If the text was edited in Windows there could be a carriage return character at the end of each line.

Code:

echo  $w | tr -d '\r'  # tr can delete carriage returns

Thanks it was the \r.