Bash: command works but not inside of for loop.

RijilV · 05-21-2006, 06:44 PM

Hey, I have a bash script: http://riji.lv/hiro.txt
In there I run the command:

Code:

find $dir -type -f $FCL

where "$FCL" is something like "( -iname *.foo -print -o -iname *.bar -print )"

This works fine if I assign it to a variable, such as:

Code:

fList=`find $dir -type f $FCL`

however when I try this in a for loop such as:

Code:

for file in $( find $dir -type -f $FCL );

I get:

Code:

find: invalid predicate `( -iname *.foo -print -o -iname *.bar -print )'

I have no idea why this is happening, I've attempted a few things, putting things in quotes, writing the variables like ${FCL} etc.. nothing seems to matter. Any ideas welcome...

jlinkels · 05-21-2006, 07:57 PM

For me this worked:

Code:

#! /bin/sh

set -f

FCL=" -iname *.pdf -print -o -iname *.html -print "
dir="/tmp"


for file in $( find $dir -type f $FCL )
do
        echo "file in loop: $file"
done

It gives this output:

Quote:

file in loop: /tmp/no.video.html
file in loop: /tmp/weg.pdf
file in loop: /tmp/X3e_61873972.pdf

Which is as expected.

Maybe you can develop this to your piece of code...

BTW, in you post you write:

Quote:

for file in $( find $dir -type -f $FCL );

Is the "minus f" a typo which does not occur in your real code?

jlinkels