BASH: check if dir do not exist

looop · 07-11-2014, 12:52 PM

Hey I want to create a dir, if it do not exist.
What I have is this

Code:

if  [ ! -d "$/usr/lib/ninja" ] && [ ! -d "$/usr/include/ninja"]; then
    mkdir /usr/lib/ninja
    echo "ninja library has been created in /usr/lib"
    mkdir /usr/include/ninja
    echo "ninja library has been created in /usr/include"

else
    echo ninja code library already existing
fi

WHAT THE f. is wrong

szboardstretcher · 07-11-2014, 12:58 PM

remove the money sign?

Also instead of using && you will want to use ||.

jailbait · 07-11-2014, 12:58 PM

What are the results when neither directory exists?

What are the results when both directories exist?

What are the results when $/usr/lib/ninja exists and $/usr/include/ninja does not exist?

What are the results when $/usr/include/ninja exists and $/usr/lib/ninja does not exist?

---------------------------
Steve Stites

looop · 07-11-2014, 01:16 PM

Thank you very much solved it

bigearsbilly · 07-22-2014, 04:35 AM

you may as well:
mkdir -p /blah/blah
and you won't get an error if it already exists.

mkdir is checking for existence anyway, little point in you doing it too.

pan64 · 07-22-2014, 05:20 AM

and, if you want a report (about creating dirs): mkdir -pv /what/ever/you/need

rtmistler · 07-25-2014, 01:05 PM

Quote:

Originally Posted by bigearsbilly

you may as well:
mkdir -p /blah/blah
and you won't get an error if it already exists.

mkdir is checking for existence anyway, little point in you doing it too.

Using the -p option would be my first choice. If I were to leave the check for existence in, I would not do a compound if statement. Test each directory individually and create versus not if you still wish to test.