BASH

Micro420 · 12-15-2006, 01:21 PM

I am learning about array variables. So according to my book, I do this:

Code:

name=(matt mark luke john xena)

is equivalent to:

Code:

name[0]=matt
name[1]=mark
name[2]=luke
name[3]=john
name[4]=xena

However, when I then do:
echo $name[2], I should get name[2]=luke
Instead, I get matt[2]. When I try echo $name[4], I get matt[4]

What's going on??

indienick · 12-15-2006, 01:22 PM

Try separating each element with a comma (,).
Also, I'm pretty sure you need to declare $name as an array (I'm not sure how to do this).

Micro420 · 12-15-2006, 01:33 PM

adding the comma did not work. It then came out to
echo $name[1] shows name[1]=matt,

I think I am doing something wrong, because even if I set the array manually, it still doesn't work.
name[0]=matt
name[1]=mark
name[2]=luke
name[3]=john
name[4]=xena

Then I do echo $name[1], I get name[1]=matt. This is confusing me. Maybe I should skip this chapter??

indienick · 12-15-2006, 03:24 PM

Hmm....

When I started messing around with BASH scripting, I learned from here.

It never failed me.

makyo · 12-15-2006, 04:28 PM

Hi.

Code:

       Any  element  of  an  array may be referenced using ${name[subscript]}.
       The braces are required to avoid conflicts with pathname expansion.

 -- man bash

Best wishes ... cheers, makyo

Micro420 · 12-15-2006, 05:49 PM

Quote:

Originally Posted by makyo

Hi.

Code:

       Any  element  of  an  array may be referenced using ${name[subscript]}.
       The braces are required to avoid conflicts with pathname expansion.

 -- man bash

Best wishes ... cheers, makyo

PERFECT! Adding the braces made it work. THANK YOU!!!! I just realized that my book used an example with the brace, but I overlooked it.