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Old 06-08-2006, 10:12 PM   #1
Blackout_08
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Registered: Jan 2004
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Bash arithmetic


I have this

echo $((00060108-1))
-bash: 00060108: value too great for base (error token is "00060108")

Im using bin/bash. I need to be able to do this statement. It only does it when the last digit is 8-9. Help please
 
Old 06-08-2006, 11:04 PM   #2
perfect_circle
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Yeah, this is because the number starts with 0.
In bash every number that starts with 0 is considered octal (having 8 as a base) and not decimal.

SO you cannot have a number starting with 0 and containing the digits 8 and 9 inside

Last edited by perfect_circle; 06-08-2006 at 11:11 PM.
 
Old 06-08-2006, 11:37 PM   #3
perfect_circle
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You may strip the leading zeros, like this for example:
Code:
skalkoto@darkstar:~$ number=000657999
skalkoto@darkstar:~$ without_zero=$(echo $number |sed 's/0*//')
skalkoto@darkstar:~$ echo "$without_zero"
657999
skalkoto@darkstar:~$
or use bc instead:
Code:
skalkoto@darkstar:~$ echo "0006999 -1" | bc
6998
skalkoto@darkstar:~$
 
  


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