awk: Using split to divide string to array. How do I find out the number of elements?

vxc69 · 02-06-2008, 11:21 AM

I'm trying to split a string by a delimiter into an array in awk. How do I find out the number of elements in the array?

Thanks,
vxc

schneidz · 02-06-2008, 11:24 AM

Code:

awk '{print "line = " $0 " record num = " NR  " num feilds = " NF}'

edit: corrected code

vxc69 · 02-06-2008, 11:27 AM

Quote:

Originally Posted by schneidz

Code:

awk '{print "line = " $0 " num records = " NR}'

Hey,

I meant that I'm splitting a string using split. Like:

Code:

split($0, a, ".")

According to the awk manual this should split $0 using period as a delimiter and store it in the array a. I want to know how I can find out how many elements are in a.

jim mcnamara · 02-06-2008, 11:34 AM

awk code snippet

Code:

arrcnt=0
for(i in a) { arrcnt++}

You can put this in a function or use it inline, arrcnt is the number of elements in the array a.

schneidz · 02-06-2008, 11:37 AM

this should work

Code:

  n = asort(data)

not sure how efficient it is.

Tinkster · 02-06-2008, 11:41 AM

Or, w/o having tested the performance difference to jim's suggestion ...

Code:

num=asort(a,d)
delete d

Cheers,
Tink

P.S.: Heh ... beat by a few minutes :}
I shouldn't open several posts at a time, really ;}

schneidz · 02-06-2008, 11:50 AM

Quote:

Originally Posted by Tinkster

Cheers,
Tink

P.S.: Heh ... beat by a few minutes :}
I shouldn't open several posts at a time, really ;}

this time, advantage schneidz .

vxc69 · 02-06-2008, 11:58 AM

n=asort(a) will work, thanks guys, hope time complexity won't be a prob for large values!

ghostdog74 · 02-06-2008, 10:23 PM

Quote:

Originally Posted by vxc69

I want to know how I can find out how many elements are in a.

Code:

n = split(.., array , ..)
print array[n]

n is the number of elements

vxc69 · 02-09-2008, 12:49 PM

Quote:

Originally Posted by ghostdog74

Code:

n = split(.., array , ..)
print array[n]

n is the number of elements

Even better. Have a feeling sorting will cause even more issues. Thanks.