[SOLVED] awk script - print number of words

MadeInGermany · 11-23-2016, 12:46 AM

@Daniel, A literal ' in a 'string' is '\''

Code:

echo 'won'\''t'

The shell splits the string in two, and the \' in between will become a literal '

danielbmartin · 11-23-2016, 06:56 AM

Quote:

Originally Posted by MadeInGermany

@Daniel, A literal ' in a 'string' is '\''

Code:

echo 'won'\''t'

The shell splits the string in two, and the \' in between will become a literal '

Thank you for solving the syntax mystery. To recap:

With this InFile ...

Code:

John likes chicken, prefers turkey, and won't eat ham.
Luke likes chicken McNuggets.

... this awk ...

Code:

awk 'BEGIN {RS="[[:space:]]"}
       {gsub(/^[[:punct:]]|[[:punct:]]$/,""); a[$0]++}
     END{print "chicken",   a["chicken"],
              "\nturkey",   a["turkey"],
              "\nham",      a["ham"],
              "\nwon'\''t", a["won'\''t"]}'  \
$InFile >$OutFile

... produced this OutFile ...

Code:

chicken 2 
turkey 1 
ham 1 
won't 1

Daniel B. Martin

danielbmartin · 11-23-2016, 03:02 PM

Just for fun I coded a non-awk solution. As always, corrections and improvements are invited.

With this InFile ...

Code:

John likes chicken, prefers turkey, and won't eat ham.
Luke likes chicken McNuggets.
Mary raises chickens and sheep.

... this code ...

Code:

egrep -wo 'chicken|turkey|ham|won'\''t' $InFile  \
|sort |uniq -c >$OutFile

... produced this OutFile ...

Code:

      2 chicken
      1 ham
      1 turkey
      1 won't

Daniel B. Martin